The current flowing though 3ohm resostor is 0.8amperes,the potential drop across the 4ohm resistor is
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v=ir
=>v=0.8× 4
=3.2V
hence the potential drop across the 4 ohm resistor is 3.2 volts
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=>v=0.8× 4
=3.2V
hence the potential drop across the 4 ohm resistor is 3.2 volts
I HOPE IT WILL HELP YOU!!!
IF YES THEN MARK ME AS BRAINLIEST!!!
☺☺☺☺
Answered by
0
If 0.8A is flowing through the 3Ω resistor, that means 0.8A is flowing through the other 3Ω resistor. This is because they are in parallel and the same resistance value. As a result, you have a combined 1.6A going through the 4Ω resistance.
By Ohm’s Law,
V = I*R
therefore V = 1.6A * 4Ω
= 6.4 Volts dropped across the 4Ω resistor.
Here is the schematic for this circuit (made with pSpice):
By Ohm’s Law,
V = I*R
therefore V = 1.6A * 4Ω
= 6.4 Volts dropped across the 4Ω resistor.
Here is the schematic for this circuit (made with pSpice):
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