THE CURRENT FLOWING THROUGH A CIRCUIT IS 0.4A AND THE TIME IS 3HRS. THEN FIND THE NO OF ELECTRONS FLOWING THROUGH THE CIRCUIT
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answer: twenty seven hundred multiplied by ten to the power minus nineteen
Explanation:
Q=IT
Q=ne
so,
IT=ne
0.4x3x60x60= n x 1.6 x 10*-19
n=0.4 x3 x 60x 60\1.6 x 10* -19
n= 2700 x 10 *-19
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