the current flowing through branch BD for the given circuit will be
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concept of Kirchoff laws
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It is a simple question
Since it is given in parallel the voltage would be same but the current would be different
Here the current flowing through BD would be I 1 + I2 and the voltage would be the net difference between the voltage supplied by the two ends of the circuit so
V(net)=V2-V1
=30-15
=15
By Ohm's law
V=IR
15=Ix3
I=15/3
I=5A
ckalamurthy:
plz can u explain how the branch bd is connected in parallel to what is it connected in parallel?
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