Question

The current flowing through the 3 ohm resistor in the circuit shown below is 3 × Z× 10^2 A the value of Z is...

Answer 1

Answer:

Explanation:

Refer image .1

Given :- Let the current How in 3Ωis i, and 6Ω is i1=1 ampere​  

i1+i2=I,

Va-Vb=i1×3Ω=i2*6,

⇒1×3=i2*6,

→1/2=1/2 ampere.

→Hence I=i1+i2=1+0.5=1.5ampere

Req=2+(3*6/3+6)=2+(3*6/9)=4Ω ,

equivalent circuit ,

Refer image .2 ,

From KVL ,

1req=v ,

v=1.5×4 ,

=6volt.

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