Question

The current in a circuit having constant resistance is tripled the power increases

Answer 1

Solution :

The power dissipated in a circuit is

p=I square R

Hence P∞I square

If I=3 I, then P=9P

Hence the power dissipated is 9 times

Answer : 9 times

Answer 2

Answer:

p=I^2×R

where I is tripled which is 3 and R is constant

so 3^2 is 3×3=9 9×R=9×1=2

So 9×1=9