Question

The current in a coil changes from 5 Amp to 10 Amp. in 10-2 sec then an emf of 50 milli volts is
induced in a coil near it. Calculate the mutual inductance of coil.​

Answer 1

Answer:

${10}^{ - 4} \: is \: the \: mutual \: inductance \: of \: coil.$

Explanation:

GIVEN

$e \: = 50 \: mili \: volt \: = {50} \: \times {10}^{ - 3} \: volt \\ e \: = \: 5 \: \times {10}^{ - 2} volt \\ di \: = i2 - i1 \\ di \: = \: (10 \: - \: 5 ) \: ampere \\ di \: = \: 5 \: ampere \\ dt \: = \: {10}^{ - 2} seconds$

e = L di/dt

L = e dt/di

L = 5 × 10^-2 × 10^-2/ 5 H

L = 10^-4 H

Here,

e is induced emf ( electromotive force).

di is the change in current

dt is the change in time

L is the mutual inductance

H is Henry , unit of mutual inductance.

MUTUAL INDUCTANCE

• It is a measure of the induction between two circuits , the ratio of the rlectromotive force (emf) in a circuit to the corresponding change of the current in a neighbouring circuit .
• It is measured in henry.
• It is denoted by H.