Question

the current in a coil of 500 turns is change from 5A to zero in 0.25.if an average emf of 50 V is induced during this interval ,the self inductance of the coil is​

Answer 1

Answer:

Inudctor opposes change in curren, as the current is decreased, the inductor will convert magnetic energy into electrical by creating a potential difference. The voltage drop across inductor is given by

V=L

dt

di

−50=L

.1

2−5

here negative sign is because voltage is increasing instead of drop across inductor

−50=L

.1

2−5

L=1.67H.

Answer 2

Answer:

The self inductance of the coil is 0.5V.s/A

Explanation:

It is given that the current in a coil of 500 turns change from 500A to 0A

Time taken to change is 0.25 s

If average emf induced is 50 V, we should calculate the self inductance of coil.

We know that $emf=-L\frac{di}{dt}$

$50=-L*\frac{(5-0)}{0.25}$

$50=-L*\frac{(5)}{0.25}$

$L=-\frac{50*0.25}{5}$

$L=-2.5$
Here, the negative sign indicates that the emf induced in the coil opposes the change in current produced.

Therefore, the self inductance is 0.5V.s/A

To know more about self inductance go to the following link:

https://brainly.in/question/1387003

To know more about emf go to the following link:

https://brainly.in/question/14949464

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