The current in a straight conductor is along northeast direction. The force experienced by the
conductor due to the presence of earths horizontal component of magnetic field is
Answers
Answered by
0
Explanation:
The horizontal component of earth's magnetic field is 3×10−5Wb/m2. the magnetic flux linked with a coil of area 1 m2 and having 5 turns, whose plane is normal to the magnetic field
Its magnitude at the Earth's surface ranges from 25 to 65 microteslas (0.25 to 0.65 gauss). Approximately, it is thefield of a magnetic dipole currently tilted at an angle of about 11 degrees with respect to Earth's rotational axis, as if there were a bar magnet placed at that angle at the center of the Earth
I hope it is helpful to you dear friend
please mark me as braillist answer
Answered by
0
Explanation:
, F=I
l
×
B
,
F=IIBsinθ
The force per unit length is,
f=
l
F
=IBsinθ
When the current is flowing from east to west,
θ=90
o
, hence,
f=IB=1×3×10
−5
=3×10
−5
Nm
−1
Similar questions