The current in an ac circuit is given by i = (3 + 4sin1007t + 4cos100nt)A. The r.m.s. value of current will be
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Explanation:
Current is given as i=I
o
+I
1
sinwt
Rms current is given by I
rms
=
T
∫
o
T
i
2
dt
∴ I
rms
=
T
∫
o
T
(I
o
2
+I
1
2
sin
2
wt+2I
o
I
1
sinwt)dt
Or I
rms
=
I
o
2
T
∫
o
T
dt
+I
1
2
T
∫
o
T
sin
2
wtdt
+2I
o
I
1
T
∫
o
T
sinwtdt
Using
T
∫
o
T
sin
2
wt
=0.5 and
T
∫
o
T
sinwt
=0
We get I
rms
=
I
o
2
T
T
+I
1
2
×0.5+2I
o
I
1
×0
⟹ I
rms
=
I
o
2
+0.5I
1
2
Given : I
o
=3 I
1
=4
⟹ I
rms
=
3
2
+0.5×4
2
=
17
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