Question

The current in lamp A is 0.20A. The potential difference (p.d.) across lamp A is 6.0V.
Calculate the resistance of lamp A.​

Answer 1

Answer:-

• Current=I=0.2A
• Potential Difference=V=6V
• Resistance=R=?

We know that

• According to ohms law

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \tt\longmapsto Resistance=\dfrac{6}{0.2}$

$\\ \tt\longmapsto Resistance=30\Omega$

Hence Resistance of Lamp A is 30Ω.

Note:-

SI unit of Resistance is ohm(Ω).

Answer 2

Answer:-

• 30 ohms is the required answer .

Given:-

• Current ,I = 0.20 A
• Potential Difference ,V = 6 v

To Find:-

• Resistance ,R

Solution:-

According to the Question

It is given that current in lamp A is 0.20A. The potential difference across lamp A is 6v.

we have to calculate the resistance of the lamp A .

Using ohm's law

• V = IR

where,

• V denote Potential Difference
• I denote Current
• R denote Resistance

Substitute the value we get

$\longrightarrow$ 6 = 0.20 × R

$\longrightarrow$ 6/0.20 = R

$\longrightarrow$ R = 6/0.20

$\longrightarrow$ R = 60/2

$\longrightarrow$ R = 30 ohms

• Hence, the resistance of the lamp A is 30 ohms.

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