Question

The current in lamp A is 0.20A. The potential difference (p.d.) across lamp A is 6.0V. Calculate the resistance of lamp A.​

Answer 1

Given:-

• Current ,I = 0.20 A
• Potential Difference ,V = 6

To Find:-

• Resistance ,R

Solution:-

According to the Question

It is given that current in lamp A is 0.20A. The potential difference across lamp A is 6v.

we have to calculate the resistance of the lamp A .

Using ohm's law

V = IR

where,

• V denote Potential Difference
• I denote Current
• R denote Resistance

Substitute the value we get

⟶ 6 = 0.20 × R

⟶ 6/0.20 = R

⟶ R = 6/0.20

⟶ R = 60/2

⟶ R = 30 ohms

Hence, the resistance of the lamp A is 30 ohms.

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Answer 2

Solution:

Current, I = 0.2 A

Potential difference, V = 6.0 V

According to Ohm's Law,

                                        $\frac{V}{I}$= R, where R is the resistance.

Hence, substitute the values of V and I in the above equation;

             R = $\frac{6}{0.2}$ = $\frac{60}{2}$ = 30 Ω

Hope it helps!