Question

The current in the 6 Ω resistance of the network shown in Fig.3 is 2A. Determine the
currents in all the branches and the applied voltage.

Answer 1

Answer:-

• Current=I=2A
• Resistance=R=6ohm
• Voltage=V=?

According to ohms law

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \sf \longmapsto \: V=IR$

$\\ \sf \longmapsto \: V=2\times 6$

$\\ \sf \longmapsto \: V=12v$

Note:-

SI unit of voltage is Volts(V)