Question

The current in the following circuit is​

Answer 1

Explanation

From the given figure, the resistance in the arms AC and BC are given in series

R' = Rᴀᴄ = + Rʙᴄ

R' = 3Ω + 3Ω = 6Ω

Now, R' is in parallel with the resistance in arm AB, So,

R = R' × Rᴀʙ/ R' + R'ᴀʙ = 6Ω × 3Ω/6Ω + 3Ω = 2Ω

Therefore, the Ohms law can be stated as

V = i R or current, i = V/R

Substituting the values, we get

i = 2/2 = 1A ( ∵ V = 2V)

∴ The current in the following circuit is 1 A !

Answer 2

Answer:

$\bigstar$ Explanation

From the given figure, the resistance in the arms AC and BC are given in series

R' = Rᴀᴄ = + Rʙᴄ

R' = 3Ω + 3Ω = 6Ω

Now, R' is in parallel with the resistance in arm AB, So,

R = R' × Rᴀʙ/ R' + R'ᴀʙ = 6Ω × 3Ω/6Ω + 3Ω = 2Ω

Therefore, the Ohms law can be stated as

V = i R or current, i = V/R

Substituting the values, we get

i = 2/2 = 1A ( ∵ V = 2V)

∴ The current in the following circuit is 1 A !