Question

The current in the given circuit will be :​

Answer 1

Answer:

0.1A

Explanation:

Let us Assume the Three Resistors as R1, R2 & R3

∴ R1 & R2 are in Series

∴Rs = R1 + R2

      = 30 + 30

      = 60 Ohms

 Rs = 60 Ohms

By putting R1 & R2 in Series, They become as a Single Resistor.

∵ R1 & R2 have became as a Single Resistor

∴ Rs & R3 are in Parallel Connection

∴ 1/Rp = 1/Rs + 1/R3

           = 1/60 + 1/30

           = 2 + 1/60

   1/Rp = 3/60

      Rp = 60/3

            = 20

       Rp = 20 Ohms

W.K.T

         V = IR

          I = V/R

          I = 2/20

          I = 1/10

          I = 0.1

          I= 0.1 A

I Hope this Explanation will be helpful to You...

Answer 2

Answer is in the attachment .

Please mark it as brainlist.....