Question

The current in the resistor R3 in the circuit as shown in the figure is

Answer 1

Answer:

The current in the resistor R3 in the circuit as shown in the figure is  Zero

Explanation:

using KVL

Potential difference across R3 = 0

According to symmetry a and b are at same potential. So current in R3 is zero.

Answer 2

Answer:

The current in the resistor R3 in the circuit as shown in the figure is zero.

Explanation:

As shown in figure:

Voltage at point $A=9V$

Voltage at point $B=9V$

Potential difference across $R_{3}=V_{a}-V_{b}$

$V_{ab}=9-9=0V$

Hence, current across resistance $R_{3},$

$\\I=\frac{V}{R_{3}}$

$I=\frac{0}{5} \\I=0A$

#SPJ3