Question

The current ina conductor varies with t as I=3t+4tsqare.whereI in amp and the in sec the electric charge flows through the section of conductor between the=1secand t=3sec
1) 100/3C 2) 127/4C3) 140/3C 4) 150/3C

Answer 1

Answer:

option (3). 140/3C

Explanation:

q = $\int\limits^3_1 ({3t+4t^2} \, )dt$

q = $\int _1^33tdt+\int _1^34t^2dt$

q = $\left[\frac{3t^2}{2}\right]^3_1+\left[\frac{4t^3}{3}\right]^3_1$

q = 12+$\frac{104}{3}$

q = $\frac{140}{3}$ C