The current of 0.5 A is drawn by a filament of electric bulb for 10 minutes .Find the amount of electric charge flow Through the circuit
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Answer:
Given parameters
Current (I) = 0.5 A
Time = 10 minutes
Time in minutes can be converted into seconds as follows
Time (t) = 10 × 60 = 600 sec
Q = I × t
Q = 0.5 × 600
Q = 300 C
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As we know electric charge (Q) is equal to the sum of current (I) and time (t)
But time is always in sec so t= 10*60 sec = 600 sec
I=Q/t
Q=It
Q = 0.5*600
Q=300 Coulomb
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But time is always in sec so t= 10*60 sec = 600 sec
I=Q/t
Q=It
Q = 0.5*600
Q=300 Coulomb
Mark me brainlest and thank me
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