The current of a stream runs at 5 kmph. A motor launch goes 25 km upstream and back again to the starting point in 275/2 minutes. The speed of the motor launch in the absence of any current is
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Answer:
22.9 km/hr
Step-by-step explanation:
let say The speed of the motor launch in the absence of any current is = M km/hr
upstream speed = M-5 km/hr
time = 25/(M-5) hr
downstream speed = M+5 km/hr
time = 25/(M+5) hr
total time=275/2 mins
= 275/120 hr
25/(M-5) + 25/(M+5) = 275/120
5/(M-5) + 5/(M+5) = 11/24
120/(M-5) + 120/(M+5) = 11
120(M+5+M-5) = 11(M^2-25)
240M = 11M^2 - 275
11M^2 - 240M - 275 = 0
M = (240 + root(69700))/22
=22.9 km/hr
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