Question

The current of a stream runs at the rate of 4 kmph.A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water?
( explain and no direct answer) ​

Answer 1

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Step-by-step explanation:

Let speed of boat in still water be x km/h

6/ (x+4) +6/( x-4) = 2

6x -24 +6x +24 = 2 ( x^2 -16)

6x = x^2–16

x^2 -6x = 16

ADD 9

x^2 -6x +9 =25

( x -3)^2 = 25

x -3 = 5

x= 8 km/h ANSWER

CHECK

6/12 + 6/4 = 0.5 + 1.5 =2 hours

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Answer 2

Answer:

Let the speed of a boat in still water=α km/hr

Let the speed of a boat in still water=α km/hrGiven speed of water(stream)=4 km/hr

Let the speed of a boat in still water=α km/hrGiven speed of water(stream)=4 km/hrSpeed of boat during downstream=(α+4)km/hr

Time to travel 6km during downstream=

α−46hr

Given

Given α+4

Given α+46 + α−4

Given α+46 + α−46 =2

Given α+46 + α−46 =23[ (α+4)(α−4)

Given α+46 + α−46 =23[ (α+4)(α−4)α+4+α−4 ]=1⇒6α=α

Given α+46 + α−46 =23[ (α+4)(α−4)α+4+α−4 ]=1⇒6α=α 2−16⇒α2 −8α+2α−16=0

Given α+46 + α−46 =23[ (α+4)(α−4)α+4+α−4 ]=1⇒6α=α 2−16⇒α2 −8α+2α−16=0⇒(α−8)(α+2)=0

Given α+46 + α−46 =23[ (α+4)(α−4)α+4+α−4 ]=1⇒6α=α 2−16⇒α2 −8α+2α−16=0⇒(α−8)(α+2)=0α=8=−2

=−2Speed of a boat in still water=8km/hr

=−2Speed of a boat in still water=8km/hrSpeed >0

Step-by-step explanation:

ha bhen dedo