The current passing through a core coil of 5 is decreasing at the rate of 2 ampere per second the emf developed across the coil is
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Answer:
The given question is incomplete.
Correct Question: The current passing through a choke coil of 5 henry is decreasing at the rate of 2 ampere/sec. What is the EMF developing across the coil?
According to Faraday's Law,
⇒ EMF = L × di/dt
Here, L refers to the Induction and di/dt refers to change of current with respect to time.
⇒ EMF = 5 H × 2 A/s
⇒ EMF = 10 H.A/s = 10 V
Therefore the EMF developed in the coil is 10 V.
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Answered by
3
Answer:
Combined formula with lens law:
As emf = - L(di/dt)
emf = - ( 5 * (-2) ) V
(-2 as current is in decreasing order.)
Therefore,
emf = 10 V
Here, L is induction
NOTE:-
In general the emf is calculated in the direction of the current.
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