The current through a 12 V tungsten filament lamp connected to a 12 V accumulator of negligible resistance is 3 A. Calculate:
(1) The resistance of the filament
(2) The power of the lamp
(3) The electrical energy in KWH consumed in 5 hours
(Easy question, please give superb answers)
Answers
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Explanation:
Given :
Potential difference (V) = 12 V
Electric current (I) = 3 A
Time taken (t) = 3 hours
To find :
Resistance (R)
Power (P)
Electrical power (W)
Solution :
Resistance:
=> Potential difference/Electric current
- 12/3
- 4 Ω
Power:
=> Potential difference × Electric current
- 12 × 3
- 36 W
Electrical energy:
=> Potential difference × Electric current × Time taken
- 12 × 3 × 5
- 180 Wh
- 0.18 KWh
Answers :
(1) 4 Ω
(2) 36 W
(3) 0.18 KWh
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