Question

The current through a bulb is 15 mA when it is connected in series to a 3.0 V source. What is the resistance of the bulb?

Answer 1

Answer:

0.2 × 10^3 Ohm

Explanation:

we know from Ohm's law that V= IR

where V = potential difference

I = current

R = resistance

now given

I = 15mA = 15 × 10^-3 A

V = 3v

therefore,

R = V/I = 3/ 15 × 10^-3

= 0.2 × 10^3 Ohm

Answer 2

Answer:

The answer is

$0.2*10^{3}$Ω

Explanation:

Resistance is used to determine how much of an electrical system is blocked. The ohm, a standard measure for impedance, is represented by the Greek letter omega. The name of the measure of impedance is derived from Georg Simon Ohm (1784–1854), a German physicist who studied the relationship between voltage, flow, and resistivity.

Resistance is a reaction against the current. If the resistance is significant, current flow will be challenging. Current can flow more freely through a low impedance. Ohms () are used to evaluate resistance.

According to Ohm's law, $V = IR$

where V = potential difference

$I = current$

$R = resistance$

now given

$I = 15mA$

  $= 15 * 10^{-3} A$

$V = 3v$

therefore,

$R=\frac{V}{I}$

   $=\frac{3}{15} *10^{-3}$

$= 0.2 * 10^3$Ω

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