Question

the current through two identical light bulbs connected in series is 0.25 A. the total voltage across both bulbs is 120 V. the resistence of a single light bulb is

Answer 1

Answer:

480 ohms

Explanation:

Given

i=0.25 A or 1/4 A

V=120v

V=iR by ohms law

R=V/i

R=120×4

R=480 Ohm

Answer 2

Answer:

240

Explanation:

Since Voltage = Current times resistance, divide 120 by 0.25 to find the resistance. Your resistance across the whole circuit = 480. Since there are two bulbs in the series circuit, the resistance of one of the bulbs is half of the resistance of the whole series circuit. 480/2 = 240