The current/voltage relationship for two resistors A and B is as shown in below
Figure. Determine the value of the resistance of each resistor and also find the
power dissipated through each resistor. with full method
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Answer:
For the resistances in parallel the equivalent resistance is less than smallest resistance in combination of resistors hence power dissipation is maximum in this case.
For the resistances in series the equivalent resistance is addition of resistors hence power dissipation is minimum in this case.
Hence, to avoid maximum power dissipation in parallel circuit R must be equal to zero so the equivalent of parallel resistors will be
R
p
=
8+0
(0)(8)
=0Ω
Since, R
p
=0Ω voltage across it is zero.
Therefore power dissipated in 2Ω resistor is
P=
R
V
2
P=
2
(12)
2
P=72W
Explanation:
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