Question

The curvature of y = sin x at (5,1) is​

Answer 1

Answer:

Given: y=sinx

To find: Eq. of normal to curve at (0,0)

Solution: y=sinx

dx

dy

​  

=cosx

dx

dy

​  

]  

(0,0)

​  

=cos0=1

Eq. of normal:

Slope of normal

=  

dx

dy

​  

 

−1

​  

=−1

Eq. of normal at (0,0) ⇒y−0=−1(x−0)

y=−x

y+x=0

∴x+y=0 is the required.

Eq. of normal to curve y=sinx at (0,0).