Question

The curve 4y = ux2 + v passes through point p at 2,3 and dy/dx = 4 this point p . so the values of u and v are​

Answer 1

Answer:

u= 4

and

v=-4

Step-by-step explanation:

$4y = u {x}^{2} + v \\ y = \dfrac{u}{4} {x}^{2} + \dfrac{ v}{4}$

Now,

$\dfrac{dy}{dx} = \dfrac{ux}{2}$

Whose value according to question is 4.

Now since this curve passes through (2,3) they must satisfy this epression too,

$\dfrac{u \times 2}{2} = 4$

Therefore u = 4 and using u in the equation fo curve along with the value of x and y we get

v= -4.

$(4)(3) = 4(4) + v \\ \implies v = - 16 + 12 = - 4$

Answer 2

Answer:

v=-4

Step-by-step explanation:

i hope my answer will help you,

thanks