Question

the curve surface area of right circular cylinder of height 7 cm is 88cmsq find the diameter of the base of the cylinder​

Answer 1

Answer:

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Step-by-step explanation:

Height (h) of cylinder = 14cm

Let the diameter of cylinder be d.

Curved Surface Area of Cylinder = 88cm square

2πrh = 88 cm square

π dh = 88 cm square. (d = 2r)

22/7 × d × 14 = 88 cm

d = 2 cm

Therefore,the diameter of the base of the cylinder is 2 cm

Answer 2

SOLUTION :

$\underline{\bf{Given\::}}}}$

• The curved surface area of right circular cylinder = 88 cm²
• Height of the cylinder (h) = 7 cm

$\underline{\bf{To\:find\::}}}}$

The diameter of the base of cylinder.

$\underline{\bf{Explanation\::}}}}$

We know that formula of the curved surface area of cylinder :

$\boxed{\bf{C.S.A.=2\pi rh\:\:\:\:\:(sq.unit)}}}}}$

A/q

$\longrightarrow\sf{2\pi rh=88}\\\\\longrightarrow\sf{2\times \dfrac{22}{\cancel{7}} \times r \times \cancel{7 }= 88}\\\\\longrightarrow\sf{44\times r=88}\\\\\longrightarrow\sf{r=\cancel{88/44}}\\\\\longrightarrow\bf{r=2\:cm}$

Now,

We know that;

$\longrightarrow\sf{Diameter=2r}\\\\\longrightarrow\sf{Diameter=2\times 2cm}\\\\\longrightarrow\bf{Diameter=4\:cm}$

Thus,

The diameter of the base of the cylinder will be 4 cm .