Question

THE CURVED SURFACE AREA OF A CYLINDER 4400CM2AND CURCUMFERENCE OF ITS BASE IS 110CM .FIND THE VOLUME OF ACYLINDER.

Answer 1

$\pi$r² = 110
r² = 110×7/22
≈6
2$\pi$rh = 4400
2×22/7×6×h=4400
h = 100×7/6
   =700/6
   =116.7
V = $\pi$r²h
   =22/7×6²×116.7
   =13203.77

Answer 2

Circumference of its base = $2 \pi r$
110/2 = 22/7*r
55 = 22/7*r
55*7/22 = r
35/2 = r
Curved surface area of the cylinder = $2 \pi rh$
4400 = 2*22/7*35/2*h
4400 = 22*5
4400/110 = h
4 = height
Volume of a cylinder = $\pi r^{2} h$
Volume of the cylinder = 22/7*4*35/2*35/2
Volume of the cylinder = 3850