Question

the curved surface area of a cylinder is 112π square meter if height of cylinder is 8m then find the cost of milk content in this vessel at the rate of rupees 45 per litre​​

Answer 1

$\huge{\mathfrak{\underline\purple{\underline\purple{Question↧}}}}$

the curved surface area of a cylinder is 112π square meter if height of cylinder is 8m then find the cost of milk content in this vessel at the rate of rupees 45 per litre.

$\huge{\mathfrak{\underline\purple{\underline\purple{αɳʂɯҽɾ↧}}}}$

${\small{\colorbox{purple}{\texttt{curved\:area\: of\:a\:circle = 2πrh}}}}$

h = $\sf\green{8m }$

$\sf\green{2πrh = 112π}$

$\sf\green{ 2×π×r×8 = 112π}$

$\sf\green{ r = 112/16 }$

$\sf\green{ r = 7m }$

$\huge\bf\purple {★Capacity\:of\:milk★}$

Volume of a cylinder is $\sf\green{πr^2h}$

so,

$\sf\green{22/7× 7×7 ×8 = 1232m^3}$

In liter it's capacity is $\sf\green{ [1232×100] }$

$\huge\bf\purple {★rate\:of\:milk\:is★}$

In one liter rate is $\sf\green{ 45 }$

so, in 1232000 liter rate is $\sf\green{ 1232000×45 =55440000rs }$

Answer 2

Question :

the curved surface area of a cylinder is 112π square meter if height of cylinder is 8m then find the cost of milk content in this vessel at the rate of rupees 45 per litre

Formula used :

Volume of cylinder = π²h

CSA of cylinder =2πrh

Solution :

We are given that

CSA = 112π m²

height of cylinder = 8 m

So, putting value

112π=2πrh

112π = 2π×r×8

56/8 = r

r = 7 m

___________________________

Volume of cylinder = πr²h

=π ×49× 8

= 392π

____________________________

Cost of milk content in the vessel

= 392π × 45

= 17640×22/7

= Rs 55440