Math, asked by sr0061017, 4 months ago

the curved surface area of a cylinder is reduced by per cent of the height is half of the original height​

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Answered by abiswasthika11
0

Answer:

Explanation: The CSA of cylinder with radius “r” and height “h” is 2πrh When the height is halved, then new CSA is 2πr (h/2) = πrh Hence, the percentage reduction in CSA = [(2πrh – πrh) (100)]/ 2πrh = 50%/862086/curved-surface-area-cylinder-reduced-cent-the-height-half-original-height

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