The curved surface area of a cylinder kal pole is 625 CM square and its volume is it 24 cm square find the diameter and height of the pole
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Answer:
Given:
CSA of pole = 264 m2
Volume of pole = 1848 m3
Formula:
CSA (curved surface of a cylinder) = 2πrh
Volume = πr2h
Where. r = radius, h = height
Calculation:
2πrh/πr2h = 264/1848
⇒ 2/r = 264/1848
⇒ r = 14 m
Now, 2 × 22/7 × 14 × h = 264
⇒ h = 3 m
∴ Height of pole = 3m
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