The curved surface area of a cylinder whose base has a diameter of 21 cm and height 48 cm is ____________.
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Answered by
1
Step-by-step explanation:
CSA of cylinder is 2×22/7×radius×height
Given
diameter =21
radius=21/2
Height =48
CSA = 2×22/7×21/2×48
= 22×21×48/7
=3168cm^2
Answered by
0
Step-by-step explanation:
r=1/2of diameter
r=10.5cm
h=48cm
curved surface area of cylinder =2×22/7×10.5×48
=2×22×1.5×48
=44×1.5×48
=44×72
=3168 sq.cm
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