Question

The curved surface area of a cylindrical pillar is 264 m² and its volume is 924 m.
Find the diameter and the height of the pillar.​

Answer 1

Answer:

curved surface area of cylinder=2×22/7×r×h

264=2×22/7×r×h

r×h=264/2×7/22

r×h=42m

h=42/r

volumeof cylinder=22/7×r^2×h

924=22/7×r^2×42/r

924=22/7×42×r

r=924/42×7/22

r=7m

diameter =2×r

d=2×7

d=14m

so,

h=42/7

h=6m

Answer 2

$\huge \underline \mathsf \red {SOLUTION:-}$

Given That:

• Curved surface area of cylinder = 264 m²
• Volume of cylinder = 924 m³

We know that,

• CSA of cylinder = 2πrh

So,

➠ 264 = 2 × 22/7 × r × h

➠ r × h = (264 × 7)/44

➠ r × h = 1848/44

➠ r × h = 42

➠ h = 42/r ……(1)

Now,

• volume of cylinder = πr²h

Substituting the value of h = 42/r in the volume equation, we get

➠ 924 = 22/7 × r² × 42/r

➠ 924r = 924 × 7

➠ r = 7 m

So,

Radius is 7 m and the diameter will be

= 7 × 2

= 14 m.

And the height of the cylinder

= h = 42/r

= 42/7

= 6 m

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