The curved surface area of a cylindrical pillar is 264 meter sq. and it's volume is 924 meter cu. Find the diameter and the height of the pillar.
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Answer:
Curved surface area of cylinder = 264 m²
2\pi rh = 2642πrh=264
2 \times \frac{22}{7} \times r \times h = 2642×
7
22
×r×h=264
r \times h = 264 \times \frac{1}{2} \times \frac{7}{22}r×h=264×
2
1
×
22
7
r \times h = 42r×h=42
h = \frac{42}{r}h=
r
42
Volume of cylinder = 924 m³
\pi {r}^{2} h = 924πr
2
h=924
Putting the value of h
\frac{22}{7} \times {r}^{2} \times \frac{42}{r} = 924
7
22
×r
2
×
r
42
=924
\frac{22}{7} \times r \times 42 = 924
7
22
×r×42=924
r = 924 \times \frac{1}{42} \times \frac{7}{22}r=924×
42
1
×
22
7
r = 7mr=7m
To find Diameter,
diameter \: \: d = 2rdiameterd=2r
d = 2 \times 7d=2×7
d = 14 \: md=14m
To find HEIGHT,
h = \frac{42}{r}h=
r
42
h = \frac{42}{7}h=
7
42
h = 6 \: mh=6m
Step-by-step explanation:
I hope it is helpful... have a great day✨
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