Question

The curved surface area of a cylindrical pillar is 264m^2 and its volume is 924^3. Find the diameter and height of the pillar .​

Answer 1

$\huge \underline \mathsf \red {SOLUTION:-}$

Given That:

• Curved surface area of cylinder = 264 m²
• Volume of cylinder = 924 m³

We know that,

• CSA of cylinder = 2πrh

So,

➠ 264 = 2 × 22/7 × r × h

➠ r × h = (264 × 7)/44

➠ r × h = 1848/44

➠ r × h = 42

➠ h = 42/r ……(1)

Now,

• volume of cylinder = πr²h

Substituting the value of h = 42/r in the volume equation, we get

➠ 924 = 22/7 × r² × 42/r

➠ 924r = 924 × 7

➠ r = 7 m

So,

Radius is 7 m and the diameter will be

= 7 × 2

= 14 m.

And the height of the cylinder

= h = 42/r

= 42/7

= 6 m

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Answer 2

Answer:

Heya!

here is your solution :)

Curved surface area of the cylinder = 264 m²

2πrh = 264 m²

r × h = 264 × ½ × 22/7

r × h = 42

h = 42 / r

Volume of cylinder = 924 m²

πr²h = 924 m²

[ Putting the value of h ]

22 / 7 × r² × 42/r = 924

22 / 7 × r × 42 = 924

r = 924 × 1/42 × 7/22

r = 7 m

For diameter =>

d = 2r

d = 2 × 7

d = 14 m

For height =>

h = 42/r

h = 42/7

h = 6 m

Hence, the height is 6 m and diameter is 14 m

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