the curved surface area of a cylindrical pillar is 264m^2 l
and it's volume is 924m^3. Find the height of the pillar.
plss
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Answered by
4
Let the radius of the cylinder is r and the height be h.
So the volume of the cylinder = πr2h
and the curved surface area is 2πrh
πr2h = 924m3 (i)
and 2πrh = 264 m2 (ii)
dividing (i) by (ii), we get
πr2h2πrh=924264or r2=72or r = 7m
So putting r = 7m, in (ii), we get
2πrh = 264m2
2 ⨯22/7 ⨯7⨯ h = 264
so h = 6 m
So the height of the pillar is 6m
So the volume of the cylinder = πr2h
and the curved surface area is 2πrh
πr2h = 924m3 (i)
and 2πrh = 264 m2 (ii)
dividing (i) by (ii), we get
πr2h2πrh=924264or r2=72or r = 7m
So putting r = 7m, in (ii), we get
2πrh = 264m2
2 ⨯22/7 ⨯7⨯ h = 264
so h = 6 m
So the height of the pillar is 6m
Answered by
4
Given That:
- Curved surface area of cylinder = 264 m²
- Volume of cylinder = 924 m³
We know that,
- CSA of cylinder = 2πrh
So,
➠ 264 = 2 × 22/7 × r × h
➠ r × h = (264 × 7)/44
➠ r × h = 1848/44
➠ r × h = 42
➠ h = 42/r ……(1)
Now,
- volume of cylinder = πr²h
Substituting the value of h = 42/r in the volume equation, we get
➠ 924 = 22/7 × r² × 42/r
➠ 924r = 924 × 7
➠ r = 7 m
So,
Radius is 7 m and the diameter will be
= 7 × 2
= 14 m.
And the height of the cylinder
= h = 42/r
= 42/7
= 6 m
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