The curved surface area of a cylindrical pillar is 264m2 and its volume is 924 m3.Find the diameter and height of the pillar
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given, c.s.a = 264 meter square, volume of cylinder = 924 meter cube, 2πrh = 264 m square, 2 × 22 by 7 × r ×h= 264 m square , r × h= 264× 7 by 44, h = 264 × 7 by 44 × r, h= 1848 by 44× r, h = 42by r, now volume of cylinder = 924 meter square, π r square × h= 924 m..........
dchikki15:
sorry this is wrong
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Given That:
- Curved surface area of cylinder = 264 m²
- Volume of cylinder = 924 m³
We know that,
- CSA of cylinder = 2πrh
So,
➠ 264 = 2 × 22/7 × r × h
➠ r × h = (264 × 7)/44
➠ r × h = 1848/44
➠ r × h = 42
➠ h = 42/r ……(1)
Now,
- volume of cylinder = πr²h
Substituting the value of h = 42/r in the volume equation, we get
➠ 924 = 22/7 × r² × 42/r
➠ 924r = 924 × 7
➠ r = 7 m
So,
Radius is 7 m and the diameter will be
= 7 × 2
= 14 m.
And the height of the cylinder
= h = 42/r
= 42/7
= 6 m
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