Question

the curved surface area of a cylindrical pillar of height 5m is 11 Sq.m. find the diameter of the pillar​

Answer 1

Answer -

• The diameter of the cylindrical piller = 0.7 m.

To find -

• The diameter of the cylindrical pillar.

Step-by-step explanation -

• Here, the curved surface area and height of a cylindrical pillar are given to us. We have to find it's diameter. Before finding the diameter of the pillar, let's find it's radius!

We know that -

$\bigstar \: \underline{ \boxed{\sf Curved \: surface \: area_{(cylinder)}=2 \pi rh}}$

Where -

• r = Radius.
• h = Height.

Here -

• Area = 11 m².
• Height = 5 m.
• π = 22/7.

Let -

• The radius of the cylindrical pillar be "r" m.

Substituting the given values in this formula -

$\implies\rm11 = 2 \times \dfrac{22}{7} \times r \times 5$

$\implies \rm11 = \dfrac{44}{7} \times 5r$

$\implies \rm11 \div \dfrac{44}{7} = 5r$

$\implies \rm11 \times \dfrac{7}{44} = 5r$

$\implies \rm \cancel{\dfrac{77}{44}} = 5r$

$\implies\rm \dfrac{7}{4} = 5r$

$\implies\rm \dfrac{7}{4} \div 5 = r$

$\implies\rm\dfrac{7}{4} \times \dfrac{1}{5} = r$

$\implies \rm\dfrac{7}{20} = r$

$\implies\rm0.35 \: m = r$

Hence -

• The radius is 0.35 m.

________________________________

• Now, let's find the diameter of the pillar!

We know that -

$\bigstar \: \underline{\boxed{\sf Diameter = 2 \times Radius}}$

Here -

• Radius = 0.35 m.

Therefore -

$\longrightarrow \tt Diameter = 0.35 \times 2$

$\longrightarrow \tt Diameter = 0.7 \: m$

Hence -

• The diameter of the cylindrical pillar is 0.7 m.

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Answer 2

Question :-

the curved surface area of a cylindrical pillar of height 5m is 11 Sq.m. find the diameter of the pillar.

Solution :-

Given :

• Area = 11sq.cm
• Height = 5m
• π = 22/7

To find :

• Diameter

Formula :

${\boxed{\sf{Curved surface are _{(Cylinder)} =2\pi rh }}}$

Calculation :

$\sf:\longmapsto{11 = 2 \times \frac{22}{7} \times r \times 5 } \\ \\ \sf:\longmapsto{ \frac{11 \times 7}{44} = r \times 5} \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{ \frac{77}{44} = r \times 5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{r = \frac{7}{4 \times 5} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{r = \frac{7}{20} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bf:\longmapsto \red{r = 0.35m} \: \: \: \: \: \: \: \: \: \: \: \:$

• Radius = 0.35m

We know that,

• Diameter = 2R

→ 2 × 0.35

→ 0.7

The diameter of the cylindrical pillar diameter is 0.7m.

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