Question

The curved surface area of a cylindrical pole is 264m2 and its volume is 924m2 . Find its height

Answer 1

height=924/264..…..........

Answer 2

Curved Surface Area = 264 m square.
$2\pi \: rh = 264 \\ \\ 2 \times \frac{22}{7} \times rh = 264 \\ \\ \frac{44}{7} \times rh = 264 \\ \\ rh = 264 \div \frac{44}{7} \\ \\ rh = 264 \times \frac{7}{44} \\ \\(264 \div 44 = 6) \\ \\ rh = 6 \times 7 \\ \\ rh = 42$



Volume = 924 m cube.
$\pi \: {r}^{2} h \: = 924 \\ \\ \frac{22}{7} \times r \times r \times h = 924 \\ \\ (r \times h = 42) \\ \\ \frac{22}{7} \times r \times 42 = 924 \\ \\ (42 \div 7 = 6) \\ \\ 22 \times 6 \times r = 924 \\ \\ 132 \times r = 924 \\ \\ r = \frac{924}{132} \\ \\ r = 7$


Radius 'r' = 7m

r X h = 42
7 X h = 42
h = 42/7
h = 6

Height 'h' = 6m