Question

The curved surface area of a right circular cylinder is 4.4m^2. If the radius of its base is 0.7m, find its (i) height and (ii) volume.

Answer 1

Given :

• Curved Surface Area of right circular cylinder = 4.4m²
• Radius of base = 0.7 m

To find :

(i) Height

(ii) Volume

Formula used :

• CSA of right circular cylinder = 2πrh
• Volume of right circular cylinder = πr²h

Solution :

(i) 2πrh = 4.4 m²

$\implies \sf \: 2 \times \dfrac{22}{7} \times 0.7 \times h = 4.4 \\ \\ \implies \sf \: h \: = \frac{4.4 \times 7}{2 \times 22 \times 0.7} \\ \\ \implies \sf \: h \: = 1 \: m$

$\sf \: (ii) volume \: = \pi {r}^{2}h \: \\ \\ \implies \sf \: volume = \: \dfrac{22}{7} \times ( {0.7}^{2}) \times 1 \\ \\ \implies \sf \: volume \: = \dfrac{22 \times 0.49}{7} \\ \\ \implies \sf \: \bold{ volume \: = 1.54 \: {m}^{3} }$

ANSWER :

(i) Height = 1 m

(ii) Volume = 1.54 m³

Answer 2

$\huge\mathbb\orange{Hey \: Mate \: :)}$

${\huge{\underline{\underline{\mathtt{\green{A}{\red{n}{\blue{s}{\pink{w}{\orange{e}{\purple{r}}}}}}}}}}}$

Let the height of the right circular cylinder be h m.

r=0.7m

Curved surface area = 4.4m²

$\longrightarrow$ 2πrh=4.4

$\longrightarrow$ 2 × $\small\dfrac{22}{7}$ × 0.7 × h = 4.4

$\longrightarrow$ 4.4h = 4.4

$\longrightarrow$ h = 1m

$\small\sf\pink{Hence, \: the \: height \: of the \: right \: circular \: cylinder \: is \: 1m}$

$\large\underline\mathbb\green{♡HOPE \: THIS \: HELPS \: U♡}$

${\huge{\red{\fbox{\colorbox{lime}{Mark \: me \: Brainliest}}}}}$