Question

the curved surface area of a right circular cylinder of height 14 cm is 88Cmsquare find the diameter of the base of the cylinder

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Answer 1

Answer:

CSA of cylinder =2*pie*r*h

88 = 2*22/7*r*14

88*7÷22*2*14 =r

r = 1

d = 2r

d =2*1

d =2

Answer 2

$\huge\bf\underline{Question:}$

The curved surface area of a right circular cylinder of height 14cm is 88sq.cm. find the diameter of the base of the cylinder.

$\huge\bf\underline{Answer:}$

Formula Used:

$\boxed{\sf{\green{CSA\: of \:Cylinder=2πrh}}}$

Put the values in the formula to get the value of r.

$88 = 2 \times \frac{22}{7} \times r \times 14 \\ 88 = 44 \times r \times 2 \\ 88r = 88$

$\boxed{\sf{\red{r=1cm}}}$

We know that, diameter is twice the radius.

$Diameter=2×Radius\\Diameter= 2×1$

$\boxed{\sf{\red{Diameter=2cm}}}$