Question

The curved surface area of a right circular cylinder of height 14cm is 88cm square diameter of the base of the cylinder
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Answer 1

Answer:

2 cm

Step-by-step explanation:

$csa = 2\pi{r}h$

$2\pi {r}h = 88 {cm}^{2}$

$\frac{2 \times 22 \times r \times 14}{7} = 88 {cm}^{2}$

$2 \times 22 \times r \times 2 = 88 {cm}^{2}$

$44 \times 2r = 88 {cm}^{2}$

$2r = \frac{88}{44}$

$2r = 2$

$d = 2 \: cm$

Answer 2

$Answer$

Question⏬

The curved surface area of a right circular cylinder of height 14cm is 88cm square diameter of the base of the cylinder .

Answer⏬

Given , The height of cylinder =14cm

Given , The height of cylinder =14cm and , the curved surface area of cylinder =88cm^2

2

2 we know that ,

2 we know that , the curved surface area of cylinder =2πrh

2 we know that , the curved surface area of cylinder =2πrhand 2r=d

2 we know that , the curved surface area of cylinder =2πrhand 2r=dhere , r=radius of cylinder , d=diameter of cylinder and h=height of cylinder

2 we know that , the curved surface area of cylinder =2πrhand 2r=dhere , r=radius of cylinder , d=diameter of cylinder and h=height of cylinderso , the curved surface area of cylinder =πdh =88cm^2

2 π×d×14=88

22/7×d×14=88

so, the diameter of the cylinder is 2cm.