the curved surface area of a right vircular cylinder eith height 14cm is 88sq.cm.the duameter of the base is
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Given:
CSA of cylinder = 88sq.cm.
Height of cylinder = 14 cm
To find:
Diameter of the base
Solution:
CSA of cylinder = 2πrh
88 = 2× 22/7 × r × 14
88 = 2 × 22 × r × 2
88 = 88 × r
r = 88/88
r = 1
So, diameter of the base = 2r = 2×1 = 2cm
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