Question

The curved surface area of a tight circular cone of height 15 cm and base diameter 16 cm is​

Answer 1

Answer:

Given

h = 15cm

d = 16

r = \frac{16}{2}

2

16

r = 8

Solution

CSA of a cone = πr\ellℓ

But we dont have the value for \ellℓ

Now,

\ellℓ = \sqrt\mathsf{r^{2} + h^{2}}

r

2

+h

2

\ellℓ = \sqrt\mathsf{8^{2} + 15^{2}}

8

2

+15

2

\ellℓ =

\ellℓ =

\ellℓ = 17

CSA of a cone = πr\ellℓ

= \frac{22}{7}

7

22

× 8 × 17

= \frac{22}{7}

7

22

× 136

= 427.42 cm²