The curved surface area of a tight circular cone of height 15 cm and base diameter 16 cm is
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2
Answer:
Given
h = 15cm
d = 16
r = \frac{16}{2}
2
16
r = 8
Solution
CSA of a cone = πr\ellℓ
But we dont have the value for \ellℓ
Now,
\ellℓ = \sqrt\mathsf{r^{2} + h^{2}}
r
2
+h
2
\ellℓ = \sqrt\mathsf{8^{2} + 15^{2}}
8
2
+15
2
\ellℓ =
\ellℓ =
\ellℓ = 17
CSA of a cone = πr\ellℓ
= \frac{22}{7}
7
22
× 8 × 17
= \frac{22}{7}
7
22
× 136
= 427.42 cm²
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