Question

the curved surface area of cylinder pole is 528 m2 and its volume is 1848 m cube find the ratio of its radius to height

Answer 1

Answer:

Ratio of its radius to height is 7 : 12

Explanation:

Given: Curved Surface are of cylinder pole = 528 m²

           Volume of the pole = 1848 m³

To find: ratio of the radius and height.

let r be the radius of the pole and h be the height of the pole.

We know that,

Curved surface area of pole = 2πrh

Volume of pole = πr²h

Now, we have

$\frac{2\pi rh}{\pi r^2h}=\frac{528}{1848}$

$\frac{2}{r}=\frac{10}{35}$

$r=\frac{35}{10}\times2$

$r=7$

Now,

Curved surface area = 528 m²

2 × π × 7 × h = 528

$2\times\frac{22}{7}\times7\times h=528$

$h=\fac{528}{22\times2}$

$h=\fac{528}{22\times2}$

h = 12

Therefore, Ratio of its radius to height is 7 : 12

Answer 2

Ratio of its radius to height = 7:12

Explanation:

Given:

Curved surface area of cylinder = 528 m²

Volume = 1848 m³

Find:

Ratio of its radius to height

Computation:

2πrh = 528

πrh = 264.......Eq1

πr²h = 1848

r(πrh) = 1848

r(264) = 1848

r = 7 m

From Eq1

h = 264 / πr

h = 12 m

Ratio of its radius to height = 7:12

Learn more:

https://brainly.in/question/16635540