Question

the curved surface area of right circrlar cylinder of height 14cm is 88cm square. find diameter of base of cylinder.​

Answer 1

Answer:

Height of cylinder = 14 cm

curved surface area = 88cm square

Step-by-step explanation:

Let radius of base of right circular cylinder= r cm

Now,

2rh = 88

2×22/7 × r× 14 = 88

r= 88 ×7/22 × 1/14 × 1/2

r= 1 cm

Diameter of the base of the cylinder = 2r

= 2×1

= 2cm

Answer 2

Answer:

Given :-

Height of cylinder = 14 cm

CSA of cylinder = 88 cm²

To Find :-

Diameter

Solution :-

As we know that

\frak \red{{CSA = 2\pi} rh}CSA=2πrh

Here,

R is the Radius

H is the Height

π is the 22/7

\tt \implies \: 88 = 2 \times \dfrac{22}{7} \times r \times 14⟹88=2×

7

22

×r×14

\tt \implies \: 88 = 2 \times 22 \times r \times 2⟹88=2×22×r×2

\tt \implies \: 88 = 88r⟹88=88r

\tt \implies \: r = \cancel \dfrac{88}{88}⟹r=

88

88

\tt \implies \: r = 1 \: cm⟹r=1cm

Now,

Let's find Diameter

$\frak \blue{Diameter \: = Radius \times 2}Diameter=Radius×2</p><p>$

\tt \implies \: Diameter = 1 \times 2⟹Diameter=1×2

{\frak {Diameter = 2 \: cm}}Diameter=2cm

Hence :-

Diameter of its base is 2 cm