Question

The curved surface area of right circular cylinder of height 14 cm is 88 cm².find the diameter the base of cylinder​(assume π = 22/7)​

Answer 1

Given :-

• Height of the cylinder = 14 cm

• CSA of cylinder = 88 cm²

To find :-

• Diameter of the base of cylinder

$\setlength{\unitlength}{1 mm}\begin{picture}(5,5)\qbezier(2,3)(8,8)(14,3)\qbezier(2,3)(8,-4)(14,3)\put(2,-27){\line(0,2){30}}\put(14,-27){\line(0,2){30}}\qbezier(2,-27)(8,-35)(14,-27)\qbezier(2,-27)(8,-20)(14,-27)\put(8,-27){\line(0,2){30}}\put(15,-17){ \sf{h = 14cm} }\put(9,-29){ \tt{} }\put(8,-27){\line(2,0){6}}\put(8,3){\line(2,0){6}}\put(15,-14){ \tt{} }\end{picture}$

Solution :-

$\bigstar$$\large{\boxed{\tt{CSA\: of \:cylinder = 2 \pi rh}}}$

➢ 88 cm² = 2πrh

➢ 88 = 2 × 22/7 × r × 14 cm

➢ r = 88 × 7/2 × 22 × 14

➢ r = 1 cm

Hence, radius of right circular cylinder is 1cm.

$\bigstar$$\large{\boxed{\tt{Diameter = 2 \times Radius}}}$

➢ 2 × 1

➢ 2 cm

Therefore, diameter of right circular cylinder is 2 cm

Answer 2

✬ Diameter = 2 cm ✬

Step-by-step explanation:

Given:

• Measure of height of right circular cylinder is 14 cm.
• Curved surface area of cylinder is 88 cm².

To Find:

• What is measure of diameter of base of cylinder ?

Solution: Let the measure of radius be h cm.

As we know that

★ C.S.A of Cylinder = 2πrh ★

A/q

• C.S.A is 88 cm². ( π = 22/7)

$\implies{\rm }$ 88 = 2πrh

$\implies{\rm }$ 88 = 2 $\times$ 22/7 $\times$ r $\times$ 14

$\implies{\rm }$ 88 = 44r/7 $\times$ 14

$\implies{\rm }$ 88 = 44r $\times$ 2

$\implies{\rm }$ 88 = 88r

$\implies{\rm }$ 88/88 = r

$\implies{\rm }$ 1 cm = Radius

So, radius of right circular cylinder is 1 cm.

Now, Diameter = 2(Radius)

➨ Diameter = 2(1) = 2 cm

Hence, Diameter of cylinder is 2 cm.