the curved surface area of right circular cylinder of height 14 cm is 88cm square find the diameter of the base of the cylinder
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Answered by
53
Height (h) of cylinder = 14 cm
Let the diameter of the cylinder be d.
Curved surface area of cylinder = 88 cm2
⇒ 2πrh = 88 cm2 (r is the radius of the base of the cylinder)
⇒ πdh = 88 cm2 (d = 2r)
⇒ d = 2 cm
Therefore, the diameter of the base of the cylinder is 2 cm.
Let the diameter of the cylinder be d.
Curved surface area of cylinder = 88 cm2
⇒ 2πrh = 88 cm2 (r is the radius of the base of the cylinder)
⇒ πdh = 88 cm2 (d = 2r)
⇒ d = 2 cm
Therefore, the diameter of the base of the cylinder is 2 cm.
Answered by
51
heya!
here's ur answer...
given the height of the cylinder is 14cm.
CSA of the cylinder=88cm²
therefore 2πrh=88cm²
→2×22/7×r×14=88cm²
→44×r×2=88cm²
→r×2=88/44
→r×2=2
→r=2/2
→r=1cm
verification:-
CSA of cylinder=2πrh
=2×22/7×1×14
=44×2
=88cm²
thus the radius of the cylinder is 1cm.
we know diameter is double of radius therefore diameter is=2×1
=2cm
hope this helps..!
here's ur answer...
given the height of the cylinder is 14cm.
CSA of the cylinder=88cm²
therefore 2πrh=88cm²
→2×22/7×r×14=88cm²
→44×r×2=88cm²
→r×2=88/44
→r×2=2
→r=2/2
→r=1cm
verification:-
CSA of cylinder=2πrh
=2×22/7×1×14
=44×2
=88cm²
thus the radius of the cylinder is 1cm.
we know diameter is double of radius therefore diameter is=2×1
=2cm
hope this helps..!
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