Question

the curved surface of a right circular cylander is 88cm² and its height is 14cm², find the diameter of a base of the cylinder​

Answer 1

Step-by-step explanation:

csa of cylinder = 2pie × radius × height

88 = 2× 22/ 7×r×14

r = (88×7)/(44×14)

r = 1

d = 2 (1)

d = 2 cm

r =

Answer 2

Answer:

Given :-

Height of cylinder = 14 cm

CSA of cylinder = 88 cm²

To Find :-

Diameter

Solution :-

As we know that

\frak \red{{CSA = 2\pi} rh}CSA=2πrh

Here,

R is the Radius

H is the Height

π is the 22/7

\tt \implies \: 88 = 2 \times \dfrac{22}{7} \times r \times 14⟹88=2×

7

22

×r×14

\tt \implies \: 88 = 2 \times 22 \times r \times 2⟹88=2×22×r×2

\tt \implies \: 88 = 88r⟹88=88r

\tt \implies \: r = \cancel \dfrac{88}{88}⟹r=

88

88

\tt \implies \: r = 1 \: cm⟹r=1cm

Now,

Let's find Diameter

\frak \blue{Diameter \: = Radius \times 2}Diameter=Radius×2

\tt \implies \: Diameter = 1 \times 2⟹Diameter=1×2

{\frak {Diameter = 2 \: cm}}Diameter=2cm

Hence :-

Diameter of its base is 2 cm

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