The customer accounts at a certain departmental store have an average balance of rs 480 and a standard deviation of rs 160 assuming that the account balances are normally distributed .what is the proportion of the accounts is over 600 and what proportion of the accounts is between rs 240 and rs 360?
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answer to s $175 mind it
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Answer:
0.1598
Step-by-step explanation:
P(240<X<360)=P( 240/160 - 480/160 <Z< 360/160 - 480/160)
=P(−1.5<Z<−0.75)=
=P(Z<-0.75)-P(Z<-1.5)=P(Z<1.5)-P(Z<0.75)==P(Z<−0.75)−P(Z<−1.5)=P(Z<1.5)−P(Z<0.75)=
=0.9332-0.7734=0.1598.=0.9332−0.7734=0.1598.
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